Problem #52

Evaluate the infinite series sum from n=2 to infinity 1/(n^3-n) = 1/6+1/24+1/60+1/120 ...

sum from n=2 to infinity 1/(n^3-n) = 1/6+1/24+1/60+1/120 ...

sum from n=2 to infinity (-1)^n/(n^3-n) = 1/6-1/24+1/60-1/120 ...

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